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Solve for c. {:[2c-2=4],[c=]:} Submit

Solve for c c .\newline2c−2=4c= \begin{array}{l} 2 c-2=4 \\ c= \end{array} \newlineSubmit

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Sine and cosine of complementary anglesright chevron icon

Full solution

Q. Solve for c c .\newline2c−2=4c= \begin{array}{l} 2 c-2=4 \\ c= \end{array} \newlineSubmit
  1. Equation 11: First equation is 2c−2=42c - 2 = 4. Let's solve for cc.
    2c−2=42c - 2 = 4
    Add 22 to both sides to isolate the term with cc.
    2c−2+2=4+22c - 2 + 2 = 4 + 2
    2c=62c = 6
  2. Solve for c: Now, divide both sides by 22 to solve for c.\newline2c2=62\frac{2c}{2} = \frac{6}{2}\newlinec=3c = 3

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