Solve for c. -15=-31-(c)/(2) Answer: c=

Isolate term with c: First, we want to isolate the term containing c on one side of the equation. -15 = -31 - (c)/(2) Add 31 to both sides to move the constant term to the left side. -15 + 31 = -31 + 31 - (c)/(2)Calculate sum on left side: Now, calculate the sum on the left side of the equation. 16 = - (c)/(2)Get rid of fraction: To solve for c, we need to get rid of the fraction by multiplying both sides by 2. 2 * 16 = cCalculate final value: Finally, calculate the product on the left side to find the value of c. 32 = c

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Solve for
c.

-15=-31-(c)/(2)
Answer:
c=

Solve for $c$ . $\newline$ $-15=-31-\frac{c}{2}$ $\newline$ Answer: $c=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

c

\newline

-15=-31-\frac{c}{2}

\newline

Answer:

c=

Isolate term with c: First, we want to isolate the term containing $c$ on one side of the equation. $\newline$ $-15 = -31 - \frac{c}{2}$ $\newline$ Add $31$ to both sides to move the constant term to the left side. $\newline$ $-15 + 31 = -31 + 31 - \frac{c}{2}$
Calculate sum on left side: Now, calculate the sum on the left side of the equation. $16 = - \frac{c}{2}$
Get rid of fraction: To solve for $c$ , we need to get rid of the fraction by multiplying both sides by $2$ . $2 \times 16 = c$
Calculate final value: Finally, calculate the product on the left side to find the value of $c$ . $32 = c$