Solve for b. (b)/(3)-45=-40 Answer: b=

Isolate term with b: First, we want to isolate the term containing b on one side of the equation. To do this, we add 45 to both sides of the equation to cancel out the -45 on the left side. (b/3) - 45 + 45 = -40 + 45Simplify both sides: Now, we simplify both sides of the equation by combining like terms. (b/3) = 5Get rid of division: To solve for b, we need to get rid of the division by 3. We do this by multiplying both sides of the equation by 3. (b/3) * 3 = 5 * 3Find the value of b: Multiplying both sides by 3 gives us the value of b. b = 15

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Solve for $b$ . $\newline$ $\frac{b}{3}-45=-40$ $\newline$ Answer: $b=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for

b

\newline

\frac{b}{3}-45=-40

\newline

Answer:

b=

Isolate term with b: First, we want to isolate the term containing $b$ on one side of the equation. To do this, we add $45$ to both sides of the equation to cancel out the $-45$ on the left side. $\newline$ $(\frac{b}{3}) - 45 + 45 = -40 + 45$
Simplify both sides: Now, we simplify both sides of the equation by combining like terms. $\frac{b}{3} = 5$
Get rid of division: To solve for $b$ , we need to get rid of the division by $3$ . We do this by multiplying both sides of the equation by $3$ . $(\frac{b}{3}) \times 3 = 5 \times 3$
Find the value of $b$ : Multiplying both sides by $3$ gives us the value of $b$ . $b = 15$