Solve for b and simplify your answer. -20=(5)/(2)b Answer:

Identify equation: Identify the equation to solve. The equation given is -20 = (5/2)b. We need to solve for b.Isolate variable b: Isolate the variable b. To isolate b, we need to multiply both sides of the equation by the reciprocal of (5/2), which is (2/5). So, we multiply both sides by (2/5) to get b on its own. (-20) * (2/5) = ((5/2)b) * (2/5)Perform multiplication: Perform the multiplication on both sides. On the left side, -20 times 2 is -40, and -40 divided by 5 is -8. On the right side, (5/2) times (2/5) is 1, so we are left with b. -8 = b

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Solve for
b and simplify your answer.

-20=(5)/(2)b
Answer:

Solve for $b$ and simplify your answer. $\newline$ $-20=\frac{5}{2} b$ $\newline$ Answer:

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Math Problems

Grade 7

Powers with negative bases

Full solution

Q. Solve for

b

and simplify your answer.

\newline

-20=\frac{5}{2} b

\newline

Answer:

Identify equation: Identify the equation to solve. $\newline$ The equation given is $-20 = \left(\frac{5}{2}\right)b$ . We need to solve for $b$ .
Isolate variable $b$ : Isolate the variable $b$ . To isolate $b$ , we need to multiply both sides of the equation by the reciprocal of $\frac{5}{2}$ , which is $\frac{2}{5}$ . So, we multiply both sides by $\frac{2}{5}$ to get $b$ on its own. $(-20) \times \frac{2}{5} = \left(\frac{5}{2}b\right) \times \frac{2}{5}$
Perform multiplication: Perform the multiplication on both sides. $\newline$ On the left side, $-20 \times 2$ is $-40$ , and $-40$ divided by $5$ is $-8$ . $\newline$ On the right side, $(5/2) \times (2/5)$ is $1$ , so we are left with $b$ . $\newline$ $-8 = b$