Solve for all values of x : x^(2)(x+9)-17 x(x+9)+72(x+9)=0 Answer: x=

Factor out common term: First, notice that each term has a common factor of (x+9). Factor out (x+9) from the equation. x^2(x+9) - 17x(x+9) + 72(x+9) = 0 (x+9)(x^2 - 17x + 72) = 0Find x for first factor: Now, we need to find the values of x that make each factor equal to zero. First, set the first factor equal to zero. x + 9 = 0 x = -9Factor and solve quadratic equation: Next, set the second factor equal to zero and solve for x. x^2 - 17x + 72 = 0 To solve this quadratic equation, we can factor it. (x - 8)(x - 9) = 0Solve for x in quadratic equation: Now, set each factor of the quadratic equation equal to zero and solve for x. x - 8 = 0 => x = 8 x - 9 = 0 => x = 9

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Solve for all values of
x :

x^(2)(x+9)-17 x(x+9)+72(x+9)=0
Answer:
x=

Solve for all values of $x$ : $\newline$ $x^{2}(x+9)-17 x(x+9)+72(x+9)=0$ $\newline$ Answer: $x=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve for all values of

x

\newline

x^{2}(x+9)-17 x(x+9)+72(x+9)=0

\newline

Answer:

x=

Factor out common term: First, notice that each term has a common factor of $(x+9)$ . Factor out $(x+9)$ from the equation. $\newline$ $x^2(x+9) - 17x(x+9) + 72(x+9) = 0$ $\newline$ $(x+9)(x^2 - 17x + 72) = 0$
Find x for first factor: Now, we need to find the values of $x$ that make each factor equal to zero. First, set the first factor equal to zero. $x + 9 = 0$ $x = -9$
Factor and solve quadratic equation: Next, set the second factor equal to zero and solve for $x$ . $x^2 - 17x + 72 = 0$ To solve this quadratic equation, we can factor it. $(x - 8)(x - 9) = 0$
Solve for x in quadratic equation: Now, set each factor of the quadratic equation equal to zero and solve for x. $\newline$ $x - 8 = 0$ => $x = 8$ $\newline$ $x - 9 = 0$ => $x = 9$