Solve for all values of x. (x)/( 10)=(5)/(2x) Answer: x=

Cross-multiply fractions: Cross-multiply to eliminate the fractions. We have (x)/(10) = (5)/(2x). To remove the fractions, we multiply both sides by 10 and 2x, which are the denominators of the fractions. So, (x * 2x) = (10 * 5)Simplify equation: Simplify the equation. Now we have 2x^2 = 50.Divide to isolate x^2: Divide both sides by 2 to isolate x^2. 2x^2 / 2 = 50 / 2 x^2 = 25Take square root: Take the square root of both sides to solve for x. √(x^2) = ±√(25) x = ±5

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Solve for all values of
x.

(x)/( 10)=(5)/(2x)
Answer:
x=

Solve for all values of $x$ . $\newline$ $\frac{x}{10}=\frac{5}{2 x}$ $\newline$ Answer: $x=$

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Math Problems

Grade 7

Powers with negative bases

Full solution

Q. Solve for all values of

x

\newline

\frac{x}{10}=\frac{5}{2 x}

\newline

Answer:

x=

Cross-multiply fractions: Cross-multiply to eliminate the fractions. $\newline$ We have $(x)/(10) = (5)/(2x)$ . To remove the fractions, we multiply both sides by $10$ and $2x$ , which are the denominators of the fractions. $\newline$ So, $(x \cdot 2x) = (10 \cdot 5)$
Simplify equation: Simplify the equation. $\newline$ Now we have $2x^2 = 50$ .
Divide to isolate $x^2$ : Divide both sides by $2$ to isolate $x^2$ . $\newline$ $\frac{2x^2}{2} = \frac{50}{2}$ $\newline$ $x^2 = 25$
Take square root: Take the square root of both sides to solve for $x$ . $\sqrt{x^2} = \pm\sqrt{25}$ $x = \pm5$