Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for all values of 
x.

(x+1)/(x-5)=(-2)/(x)
Answer: 
x=

Solve for all values of x x .\newlinex+1x5=2x \frac{x+1}{x-5}=\frac{-2}{x} \newlineAnswer: x= x=

Full solution

Q. Solve for all values of x x .\newlinex+1x5=2x \frac{x+1}{x-5}=\frac{-2}{x} \newlineAnswer: x= x=
  1. Cross-Multiply: First, we need to cross-multiply to eliminate the fractions and get a clearer equation to work with. (x+1)×x=(2)×(x5) (x + 1) \times x = (-2) \times (x - 5)
  2. Distribute Terms: Now, we distribute the terms on both sides of the equation. x2+x=2x+10x^2 + x = -2x + 10
  3. Bring Terms Together: Next, we bring all terms to one side of the equation to set it equal to zero and solve for xx.x2+x+2x10=0x^2 + x + 2x - 10 = 0
  4. Combine Like Terms: Combine like terms to simplify the equation. x2+3x10=0x^2 + 3x - 10 = 0
  5. Factor Quadratic Equation: Now, we need to factor the quadratic equation, if possible, to find the values of xx.(x+5)(x2)=0(x + 5)(x - 2) = 0
  6. Set Factors Equal: Set each factor equal to zero and solve for xx.x+5=0x + 5 = 0 or x2=0x - 2 = 0
  7. Solve for xx (11): Solve the first equation for xx.x=5x = -5
  8. Solve for xx (22): Solve the second equation for xx.x=2x = 2
  9. Check Solutions: We must check the solutions to ensure they do not make the original equation undefined by making the denominator zero.\newlineFor x=5x = -5, the original equation becomes 5+155=410\frac{-5+1}{-5-5}=\frac{-4}{-10}, which is valid.\newlineFor x=2x = 2, the original equation becomes 2+125=33\frac{2+1}{2-5}=\frac{3}{-3}, which is also valid.

More problems from Simplify variable expressions using properties