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Solve. 3(2z-4)=30 Answer: z=

Solve.\newline3(2z−4)=30 3(2 z-4)=30 \newlineAnswer: z= z=

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Full solution

Q. Solve.\newline3(2z−4)=30 3(2 z-4)=30 \newlineAnswer: z= z=
  1. Distribute 33 into parentheses: Distribute the 33 into the parentheses.3(2z−4)=3×2z+3×(−4)3(2z - 4) = 3\times 2z + 3\times (-4) =6z−12= 6z - 12
  2. Set equation equal to 3030: Set the equation equal to 3030 and solve for 6z6z.
    6z−12=306z - 12 = 30
    Add 1212 to both sides to isolate the term with zz.
    6z−12+12=30+126z - 12 + 12 = 30 + 12
    6z=426z = 42
  3. Divide both sides by 66: Divide both sides by 66 to solve for zz.6z6=426\frac{6z}{6} = \frac{42}{6}z=7z = 7

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