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Solve. 2(2z-10)=12 Answer: z=

Solve.\newline2(2z−10)=12 2(2 z-10)=12 \newlineAnswer: z= z=

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Full solution

Q. Solve.\newline2(2z−10)=12 2(2 z-10)=12 \newlineAnswer: z= z=
  1. Distribute and Simplify: Distribute the 22 into the parentheses.2(2z−10)=122(2z - 10) = 12=2×2z+2×(−10)= 2 \times 2z + 2 \times (-10)=4z−20= 4z - 20
  2. Addition to Isolate: Add 2020 to both sides to isolate the term with zz.\newline4z−20+20=12+204z - 20 + 20 = 12 + 20\newline4z=324z = 32
  3. Division to Solve: Divide both sides by 44 to solve for zz.\newline4z4=324\frac{4z}{4} = \frac{32}{4}\newlinez=8z = 8

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