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Let’s check out your problem:
Simplify the expression:
\newline
(
3
+
k
)
+
1
=
(3 + k) + 1 =
(
3
+
k
)
+
1
=
_____
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Math Problems
Algebra 1
Simplify linear expressions using properties
Full solution
Q.
Simplify the expression:
\newline
(
3
+
k
)
+
1
=
(3 + k) + 1 =
(
3
+
k
)
+
1
=
_____
Apply Associative Property:
Apply the associative property of addition to simplify the expression.
\newline
Associative property:
(
a
+
b
)
+
c
=
a
+
(
b
+
c
)
(a + b) + c = a + (b + c)
(
a
+
b
)
+
c
=
a
+
(
b
+
c
)
\newline
(
3
+
k
)
+
1
=
3
+
(
k
+
1
)
(3 + k) + 1 = 3 + (k + 1)
(
3
+
k
)
+
1
=
3
+
(
k
+
1
)
Simplify by Adding Constants:
Simplify the expression by adding the constants.
3
+
(
k
+
1
)
=
3
+
k
+
1
3 + (k + 1) = 3 + k + 1
3
+
(
k
+
1
)
=
3
+
k
+
1
Combine Constants:
Combine the constants.
\newline
3
+
k
+
1
=
3
+
1
+
k
3 + k + 1 = 3 + 1 + k
3
+
k
+
1
=
3
+
1
+
k
Perform Addition:
Perform the addition of the constants.
3
+
1
+
k
=
4
+
k
3 + 1 + k = 4 + k
3
+
1
+
k
=
4
+
k
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What is the midline equation of
\newline
y
=
−
9
cos
(
π
2
x
−
6
)
+
8
?
y
=
□
\begin{array}{l} y=-9 \cos \left(\frac{\pi}{2} x-6\right)+8 ? \\ y=\square \end{array}
y
=
−
9
cos
(
2
π
x
−
6
)
+
8
?
y
=
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Question
z
=
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i
−
45
z=11.1 i-45
z
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45
\newline
Re
(
z
)
=
Im
(
z
)
=
\begin{array}{l}\operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Re
(
z
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Im
(
z
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Question
(
−
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−
(
14
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(-14+3 i)-(14 i)=
(
−
14
+
3
i
)
−
(
14
i
)
=
\newline
Express your answer in the form
(
a
+
b
i
)
(a+b i)
(
a
+
bi
)
.
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Posted 10 months ago
Question
(
12
−
9
i
)
+
(
32
−
6
i
)
=
(12-9 i)+(32-6 i)=
(
12
−
9
i
)
+
(
32
−
6
i
)
=
\newline
Express your answer in the form
(
a
+
b
i
)
(a+b i)
(
a
+
bi
)
.
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Posted 10 months ago
Question
What happens to the value of the expression
3
y
2
y
\frac{3 y}{2 y}
2
y
3
y
as
y
y
y
increases?
\newline
Choose
1
1
1
answer:
\newline
(A) It increases.
\newline
(B) It decreases.
\newline
(C) It stays the same.
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Posted 10 months ago
Question
Find the following trigonometric values.
\newline
Express your answers exactly.
\newline
cos
(
7
π
4
)
=
□
sin
(
7
π
4
)
=
□
\begin{array}{l} \cos \left(\frac{7 \pi}{4}\right)=\square \\ \sin \left(\frac{7 \pi}{4}\right)=\square \end{array}
cos
(
4
7
π
)
=
□
sin
(
4
7
π
)
=
□
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Posted 10 months ago
Question
Which equation has a constant of proportionality equal to
3
3
3
?
\newline
Choose
1
1
1
answer:
\newline
(A)
y
=
8
5
x
y=\frac{8}{5} x
y
=
5
8
x
\newline
(B)
y
=
1
3
x
y=\frac{1}{3} x
y
=
3
1
x
\newline
(C)
y
=
1
4
x
y=\frac{1}{4} x
y
=
4
1
x
\newline
(D)
y
=
18
6
x
y=\frac{18}{6} x
y
=
6
18
x
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
5
8
+
(
−
8
5
)
=
-\frac{5}{8}+\left(-\frac{8}{5}\right)=
−
8
5
+
(
−
5
8
)
=
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
1
4
−
(
−
3
5
)
=
-\frac{1}{4}-\left(-\frac{3}{5}\right)=
−
4
1
−
(
−
5
3
)
=
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
1
3
−
(
−
3
5
)
=
-\frac{1}{3}-\left(-\frac{3}{5}\right)=
−
3
1
−
(
−
5
3
)
=
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Posted 9 months ago
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