Simplify. Express your answer using positive exponents. (2k^9)(10k^8)(9k^2) ______

Multiply Coefficients: Multiply the coefficients (numerical parts) of the expression. We have the coefficients 2, 10, and 9. Multiplying these together gives us: 2 * 10 * 9 = 180Apply Product Rule: Apply the product rule for exponents to the variables. The product rule states that when multiplying like bases, you add the exponents. We have k^9, k^8, and k^2. Adding the exponents gives us: 9 + 8 + 2 = 19 So k^9 * k^8 * k^2 = k^(9+8+2) = k^19Combine Results: Combine the results from Step 1 and Step 2 to get the final simplified expression. We have the coefficient 180 from Step 1 and the variable part k^19 from Step 2. Combining these gives us: 180k^19

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Simplify. Express your answer using positive exponents. $\newline$ $(2k^9)(10k^8)(9k^2)$

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Grade 8

Multiply and divide powers: variable bases

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Q. Simplify. Express your answer using positive exponents.

\newline

(2k^9)(10k^8)(9k^2)

Multiply Coefficients: Multiply the coefficients (numerical parts) of the expression. $\newline$ We have the coefficients $2$ , $10$ , and $9$ . Multiplying these together gives us: $\newline$ $2 \times 10 \times 9 = 180$
Apply Product Rule: Apply the product rule for exponents to the variables. $\newline$ The product rule states that when multiplying like bases, you add the exponents. We have $k^9$ , $k^8$ , and $k^2$ . Adding the exponents gives us: $\newline$ $9 + 8 + 2 = 19$ $\newline$ So $k^9 \times k^8 \times k^2 = k^{9+8+2} = k^{19}$
Combine Results: Combine the results from Step $1$ and Step $2$ to get the final simplified expression. $\newline$ We have the coefficient $180$ from Step $1$ and the variable part $k^{19}$ from Step $2$ . Combining these gives us: $\newline$ $180k^{19}$