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Let’s check out your problem:
Simplify. Express your answer using positive exponents.
\newline
2
y
7
2
y
⋅
y
8
\frac{2y^7}{2y \cdot y^8}
2
y
⋅
y
8
2
y
7
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Math Problems
Algebra 1
Simplify exponential expressions using the multiplication and division rules
Full solution
Q.
Simplify. Express your answer using positive exponents.
\newline
2
y
7
2
y
⋅
y
8
\frac{2y^7}{2y \cdot y^8}
2
y
⋅
y
8
2
y
7
Identify and simplify:
Identify and simplify the expression by separating coefficients and variables.
2
y
7
2
y
⋅
y
8
=
2
y
7
2
⋅
y
1
⋅
y
8
\frac{2y^7}{2y \cdot y^8} = \frac{2y^7}{2 \cdot y^1 \cdot y^8}
2
y
⋅
y
8
2
y
7
=
2
⋅
y
1
⋅
y
8
2
y
7
Combine y terms:
Combine the y terms in the denominator.
\newline
2
⋅
y
1
⋅
y
8
=
2
⋅
y
(
1
+
8
)
=
2
⋅
y
9
2 \cdot y^1 \cdot y^8 = 2 \cdot y^{(1+8)} = 2 \cdot y^9
2
⋅
y
1
⋅
y
8
=
2
⋅
y
(
1
+
8
)
=
2
⋅
y
9
Rewrite with simplified denominator:
Rewrite the original expression with the simplified denominator.
2
y
7
2
×
y
9
=
2
y
7
2
y
9
\frac{2y^7}{2 \times y^9} = \frac{2y^7}{2y^9}
2
×
y
9
2
y
7
=
2
y
9
2
y
7
Simplify expression:
Simplify the expression by canceling and subtracting exponents.
\newline
2
y
7
2
y
9
=
2
2
⋅
y
7
−
9
=
1
⋅
y
−
2
=
y
−
2
\frac{2y^7}{2y^9} = \frac{2}{2} \cdot y^{7-9} = 1 \cdot y^{-2} = y^{-2}
2
y
9
2
y
7
=
2
2
⋅
y
7
−
9
=
1
⋅
y
−
2
=
y
−
2
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\newline
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\newline
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\newline
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