Select the outlier in the data set.2,73,77,78,79,82,84,88,98If the outlier were removed from the data set, would the mean increase or decrease?Choices:(A)increase(B)decrease
Q. Select the outlier in the data set.2,73,77,78,79,82,84,88,98If the outlier were removed from the data set, would the mean increase or decrease?Choices:(A)increase(B)decrease
Identify Outlier: Identify the outlier in the data set.To find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 2 stands out as being much lower than all other numbers, which are all 73 or higher.
Determine Outlier Using IQR: Determine if 2 is an outlier using the interquartile range (IQR) method.First, we need to find the first quartile (Q1) and the third quartile (Q3) of the data set. Since there are 9 numbers, the middle number is the median, which is 79. The lower half of the data set is 2,73,77,78, and the upper half is 82,84,88,98. The median of the lower half is 75 (the average of 73 and 77), and the median of the upper half is Q10 (the average of Q11 and Q12). Therefore, Q1 is 75 and Q3 is Q10.Next, calculate the IQR: Q17.Now, calculate the lower bound for outliers: Q18.Since 2 is less than Q30, it is an outlier.
Calculate Mean with Outlier: Calculate the mean of the data set with and without the outlier.First, calculate the mean with the outlier included:Mean = (2+73+77+78+79+82+84+88+98)/9Mean = 661/9Mean ≈73.44Next, calculate the mean without the outlier:Mean = (73+77+78+79+82+84+88+98)/8Mean = 659/8Mean ≈82.38
Determine Mean Change: Determine if the mean would increase or decrease without the outlier. Comparing the two means calculated in Step 3, we see that the mean without the outlier (82.38) is higher than the mean with the outlier (73.44). Therefore, removing the outlier would increase the mean.
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