Jerry has a large car which holds 22 gallons of fuel and gets 20 miles per gallon. Kate has a smaller car which holds 16.5 gallons of fuel and gets 30 miles per gallon. If both cars have a full tank of fuel now and drive the same distance, in how many miles will the remaining fuel in each tank be the same?Choose 1 answer:(A) 320(B) 325(C) 330(D) 335
Q. Jerry has a large car which holds 22 gallons of fuel and gets 20 miles per gallon. Kate has a smaller car which holds 16.5 gallons of fuel and gets 30 miles per gallon. If both cars have a full tank of fuel now and drive the same distance, in how many miles will the remaining fuel in each tank be the same?Choose 1 answer:(A) 320(B) 325(C) 330(D) 335
Set up an equation based on the fuel consumption: Let x be the number of miles driven.For Jerry's car: Fuel consumption rate: 20 miles per gallon Initial fuel: 22 gallons For Kate's car: Fuel consumption rate: 30 miles per gallon Initial fuel: 16.5 gallons Setting up the equation: 22−20x=16.5−30x
Isolating the term x:22−20x=16.5−30xAdd 20x to both sides of the equation: 22−20x+20x=16.5−30x+20x22=16.5−30x+20xSubtract 16.5 from both sides: 22−16.5=16.5−30x+20x−16.55.5=20x−30x
Simplify the equation: To simplify, let's find a common denominator, which is 60: 5.5=603x−602x5.5=60x
Solving for the value of x: To solve for x multiply both sides of the equation by 60:5.5×60=60x×60x=330The remaining fuel in each tank will be the same in 330 miles.