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Select the outlier in the data set.\newline11,13,15,18,19,20,23,27,92411, 13, 15, 18, 19, 20, 23, 27, 924\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline11,13,15,18,19,20,23,27,92411, 13, 15, 18, 19, 20, 23, 27, 924\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 11,13,15,18,19,20,23,27,92411, 13, 15, 18, 19, 20, 23, 27, 924.\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, 924924 is much larger than all other values, so it is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and divide by the number of data points.\newlineMean = (11+13+15+18+19+20+23+27+924)/9(11 + 13 + 15 + 18 + 19 + 20 + 23 + 27 + 924) / 9\newlineMean = 1070/91070 / 9\newlineMean ≈118.89\approx 118.89
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier 924924 and calculate the new mean.\newlineMean without outlier = (11+13+15+18+19+20+23+27)/8(11 + 13 + 15 + 18 + 19 + 20 + 23 + 27) / 8\newlineMean without outlier = 146/8146 / 8\newlineMean without outlier = 18.2518.25
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The original mean with the outlier was approximately 118.89118.89, and the mean without the outlier is 18.2518.25. Removing the outlier significantly decreases the mean.

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