We want to factor the following expression:x4−14x2+49Which pattern can we use to factor the expression?U and V are either constant integers or single-variable expressions.Choose 1 answer:(A) (U+V)2 or (U−V)2(B) (U+V)(U−V)(C) We can't use any of the patterns.
Q. We want to factor the following expression:x4−14x2+49Which pattern can we use to factor the expression?U and V are either constant integers or single-variable expressions.Choose 1 answer:(A) (U+V)2 or (U−V)2(B) (U+V)(U−V)(C) We can't use any of the patterns.
Rephrasing the problem: First, let's rephrase the "What pattern can be used to factor the expression x4−14x2+49?"
Identifying the structure: Identify the structure of the given expression: x4−14x2+49. Notice that it resembles the structure of a perfect square trinomial, which is a2−2ab+b2 or a2+2ab+b2, where the first and last terms are perfect squares and the middle term is twice the product of the square roots of the first and last terms.
Checking for perfect squares: Determine if the first term x4 and the last term 49 are perfect squares. The first term x4 is a perfect square because (x2)2=x4. The last term 49 is a perfect square because 72=49.
Verifying the middle term: Check if the middle term −14x2 fits the pattern of twice the product of the square roots of the first and last terms. The square root of x4 is x2, and the square root of 49 is 7, so twice the product of x2 and 7 is 2×x2×7=14x2. Since the middle term is −14x2, it fits the pattern of a perfect square trinomial with a negative middle term, which corresponds to (a−b)2.
Writing as a perfect square trinomial: Write the expression as a perfect square trinomial using the pattern (a−b)2, where a is the square root of the first term and b is the square root of the last term. In this case, a=x2 and b=7, so the factored form is (x2−7)2.
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