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Select the outlier in the data set.\newline6,62,80,82,84,88,92,996, 62, 80, 82, 84, 88, 92, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline6,62,80,82,84,88,92,996, 62, 80, 82, 84, 88, 92, 99\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 6,62,80,82,84,88,92,996, 62, 80, 82, 84, 88, 92, 99.\newlineAn outlier is a data point that is significantly different from the rest of the data. We can use the interquartile range (IQR) method to identify outliers, but in this case, we can visually inspect the data set and see that the number 66 is much lower than all other numbers, which are relatively close to each other.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineMean = (6+62+80+82+84+88+92+99)/8(6 + 62 + 80 + 82 + 84 + 88 + 92 + 99) / 8\newlineMean = (593)/8(593) / 8\newlineMean = 74.12574.125
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (62+80+82+84+88+92+99)/7(62 + 80 + 82 + 84 + 88 + 92 + 99) / 7\newlineMean without outlier = (587)/7(587) / 7\newlineMean without outlier = 83.85783.857 approximately.
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean with the outlier is 74.12574.125, and the mean without the outlier is approximately 83.85783.857. Since the mean without the outlier is higher, removing the outlier would increase the mean.

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