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Select all of the equations below that are equivalent to:\newlinez+2=7z + 2 = 7\newlineUse properties of equality.\newlineMulti-select Choices:\newline(A) 33z+99=337-33z + -99 = -33 \cdot 7\newline(B) 2z+6=272z + 6 = 2 \cdot 7\newline(C) 32z+64=32732z + 64 = 32 \cdot 7\newline(D) 23z+92=237-23z + -92 = -23 \cdot 7

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Q. Select all of the equations below that are equivalent to:\newlinez+2=7z + 2 = 7\newlineUse properties of equality.\newlineMulti-select Choices:\newline(A) 33z+99=337-33z + -99 = -33 \cdot 7\newline(B) 2z+6=272z + 6 = 2 \cdot 7\newline(C) 32z+64=32732z + 64 = 32 \cdot 7\newline(D) 23z+92=237-23z + -92 = -23 \cdot 7
  1. Check Equation (A): To determine if the equations are equivalent, we need to check if they can be simplified or transformed into the form z+2=7z + 2 = 7 by using properties of equality, such as multiplication or division by the same non-zero number on both sides of the equation.
  2. Check Equation (B): Let's start with option (A): 33z+99=337-33z + -99 = -33 \cdot 7\newlineWe can simplify this by dividing both sides by 33-33 to see if we get the original equation.\newline33z/33+99/33=337/33-33z / -33 + -99 / -33 = -33 \cdot 7 / -33\newlinez+3=7z + 3 = 7\newlineThis is not equivalent to z+2=7z + 2 = 7 because the constant term is different.
  3. Check Equation (C): Now let's check option (B): 2z+6=272z + 6 = 2 \cdot 7\newlineDivide both sides by 22 to see if it simplifies to the original equation.\newline2z2+62=272\frac{2z}{2} + \frac{6}{2} = \frac{2 \cdot 7}{2}\newlinez+3=7z + 3 = 7\newlineThis is also not equivalent to z+2=7z + 2 = 7 because the constant term is different.
  4. Check Equation (D): Next, let's examine option (C): 32z+64=32732z + 64 = 32 \cdot 7 Divide both sides by 3232 to check for equivalence. 32z32+6432=32732\frac{32z}{32} + \frac{64}{32} = \frac{32 \cdot 7}{32} z+2=7z + 2 = 7 This is equivalent to the original equation z+2=7z + 2 = 7.
  5. Check Equation (D): Next, let's examine option (C): 32z+64=32732z + 64 = 32 \cdot 7 Divide both sides by 3232 to check for equivalence. 32z32+6432=32732\frac{32z}{32} + \frac{64}{32} = \frac{32 \cdot 7}{32} z+2=7z + 2 = 7 This is equivalent to the original equation z+2=7z + 2 = 7.Finally, let's look at option (D): 23z+92=237-23z + -92 = -23 \cdot 7 Divide both sides by 23-23 to check for equivalence. 23z23+9223=23723\frac{-23z}{-23} + \frac{-92}{-23} = \frac{-23 \cdot 7}{-23} z+4=7z + 4 = 7 This is not equivalent to z+2=7z + 2 = 7 because the constant term is different.

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