Select all of the equations below that are equivalent to: 29 = 7 + u Use properties of equality. Multi-select Choices: (A)87 = 3(7 + u) (B)–11 · 29 = –77 + –11u (C)–87 = –3(7 + u) (D)–6 · 29 = –42 + –6u

Original Equation Analysis: We start with the original equation: 29 = 7 + u To determine if the other equations are equivalent, we need to apply the same operations to both sides of the original equation and see if we can obtain the equations given in the choices.Choice (A) Evaluation: Let's analyze choice (A) 87 = 3(7 + u). To check if it's equivalent, we multiply both sides of the original equation by 3: 3 * 29 = 3 * (7 + u) 87 = 21 + 3u This is not the same as choice (A), which has 87 = 3(7 + u) without distributing the 3.Choice (B) Evaluation: Now let's analyze choice (B) –11 · 29 = –77 + –11u. To check if it's equivalent, we multiply both sides of the original equation by -11: -11 * 29 = -11 * (7 + u) -319 = -77 - 11u This is not the same as choice (B), which has –11 · 29 = –77 + –11u. There is a mistake in the sign after -77; it should be a minus, not a plus.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Select all of the equations below that are equivalent to: $\newline$ $29 = 7 + u$ $\newline$ Use properties of equality. $\newline$ Multi-select Choices: $\newline$ (A) $87 = 3(7 + u)$ $\newline$ (B) $–11 \cdot 29 = –77 + –11u$ $\newline$ (C) $–87 = –3(7 + u)$ $\newline$ (D) $–6 \cdot 29 = –42 + –6u$

View step-by-step help

Home

Math Problems

Algebra 1

Identify equivalent equations

Full solution

Q. Select all of the equations below that are equivalent to:

\newline

29 = 7 + u

\newline

Use properties of equality.

\newline

Multi-select Choices:

\newline

(A)

87 = 3(7 + u)

\newline

(B)

–11 \cdot 29 = –77 + –11u

\newline

(C)

–87 = –3(7 + u)

\newline

(D)

–6 \cdot 29 = –42 + –6u

Original Equation Analysis: We start with the original equation: $\newline$ $29 = 7 + u$ $\newline$ To determine if the other equations are equivalent, we need to apply the same operations to both sides of the original equation and see if we can obtain the equations given in the choices.
Choice (A) Evaluation: Let's analyze choice (A) $87 = 3(7 + u)$ . To check if it's equivalent, we multiply both sides of the original equation by $3$ : $3 \times 29 = 3 \times (7 + u)$ $87 = 21 + 3u$ This is not the same as choice (A), which has $87 = 3(7 + u)$ without distributing the $3$ .
Choice (B) Evaluation: Now let's analyze choice (B) $–11 \cdot 29 = –77 + –11u$ . To check if it's equivalent, we multiply both sides of the original equation by $-11$ : $-11 \cdot 29 = -11 \cdot (7 + u)$ $-319 = -77 - 11u$ This is not the same as choice (B), which has $–11 \cdot 29 = –77 + –11u$ . There is a mistake in the sign after $-77$ ; it should be a minus, not a plus.