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Select all of the equations below that are equivalent to:\newline14=f+32-14 = f + 32\newlineUse properties of equality.\newline\newlineMulti-select Choices:\newline(A) 214=2f+64-2 \cdot -14 = -2f + -64\newline(B) 214=2f+68-2 \cdot -14 = -2f + -68\newline(C) 314=3f+96-3 \cdot -14 = -3f + -96\newline(D) 314=3f+99-3 \cdot -14 = -3f + -99

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Q. Select all of the equations below that are equivalent to:\newline14=f+32-14 = f + 32\newlineUse properties of equality.\newline\newlineMulti-select Choices:\newline(A) 214=2f+64-2 \cdot -14 = -2f + -64\newline(B) 214=2f+68-2 \cdot -14 = -2f + -68\newline(C) 314=3f+96-3 \cdot -14 = -3f + -96\newline(D) 314=3f+99-3 \cdot -14 = -3f + -99
  1. Apply Operation: To determine if the equations are equivalent, we need to apply the same operation to both sides of the original equation and see if we get the equations in the choices.\newlineLet's start with choice (A): Multiply both sides of the original equation by 2–2.\newlineCalculation: (2)×(14)=(2)×(f+32)(–2) \times (–14) = (–2) \times (f + 32)
  2. Check Choice (A): Now, let's simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64
  3. Check Choice (B): We can see that the result matches choice (A)(A). So, choice (A)(A) is equivalent to the original equation.
  4. Check Choice (C): Next, let's check choice (B) by multiplying both sides of the original equation by 2–2.\newlineCalculation: (2)×(14)=(2)×(f+32)(–2) \times (–14) = (–2) \times (f + 32)
  5. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64
  6. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.
  7. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32)
  8. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96
  9. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96 We can see that the result matches choice (C).\newlineSo, choice (C) is equivalent to the original equation.
  10. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96 We can see that the result matches choice (C).\newlineSo, choice (C) is equivalent to the original equation.Finally, let's check choice (D) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32)
  11. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96 We can see that the result matches choice (C).\newlineSo, choice (C) is equivalent to the original equation.Finally, let's check choice (D) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96
  12. Check Choice (D): Simplify the right side of the equation.\newlineCalculation: 28=2f6428 = -2f - 64 We can see that the result does not match choice (B) because choice (B) has 68-68 instead of 64-64.\newlineSo, choice (B) is not equivalent to the original equation.Now, let's check choice (C) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96 We can see that the result matches choice (C).\newlineSo, choice (C) is equivalent to the original equation.Finally, let's check choice (D) by multiplying both sides of the original equation by 3-3.\newlineCalculation: (3)×(14)=(3)×(f+32)(-3) \times (-14) = (-3) \times (f + 32) Simplify the right side of the equation.\newlineCalculation: 42=3f9642 = -3f - 96 We can see that the result does not match choice (D) because choice (D) has 99-99 instead of 68-6800.\newlineSo, choice (D) is not equivalent to the original equation.

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