Select all of the equations below that are equivalent to: –71p = 25 Use properties of equality. Multi-select Choices: (A)–71p/5 = 5 (B)–71p/–5 = –4 (C)–71p/–5 = –5 (D)–71p/5 = 3

Analyze Equation and Choices: Step 1: Analyze the original equation and the choices given. Original equation: –71p = 25. Choices involve dividing both sides of the original equation by a number.Check Choice (A): Step 2: Check choice (A) –71p/5 = 5. Divide both sides of the original equation by 5: (–71p)/5 = 25/5, –14.2p = 5. This does not match choice (A) since –14.2p ≠ 5.Check Choice (B): Step 3: Check choice (B) –71p/–5 = –4. Divide both sides of the original equation by –5: (–71p)/–5 = 25/–5, 14.2p = –5. This does not match choice (B) since 14.2p ≠ –4.Check Choice (C): Step 4: Check choice (C) –71p/–5 = –5. Continue from the calculation in Step 3: 14.2p = –5. This matches choice (C) since 14.2p = –5.Check Choice (D): Step 5: Check choice (D) –71p/5 = 3. Divide both sides of the original equation by 5: (–71p)/5 = 25/5, –14.2p = 5. This does not match choice (D) since –14.2p ≠ 3.

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Select all of the equations below that are equivalent to: $\newline$ $-71p = 25$ $\newline$ Use properties of equality. $\newline$ $\newline$ Multi-select Choices: $\newline$ (A) $-\frac{71p}{5} = 5$ $\newline$ (B) $-\frac{71p}{-5} = -4$ $\newline$ (C) $-\frac{71p}{-5} = -5$ $\newline$ (D) $-\frac{71p}{5} = 3$

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Math Problems

Algebra 1

Identify equivalent equations

Full solution

Q. Select all of the equations below that are equivalent to:

\newline

-71p = 25

\newline

Use properties of equality.

\newline

\newline

Multi-select Choices:

\newline

(A)

-\frac{71p}{5} = 5

\newline

(B)

-\frac{71p}{-5} = -4

\newline

(C)

-\frac{71p}{-5} = -5

\newline

(D)

-\frac{71p}{5} = 3

Analyze Equation and Choices: Step $1$ : Analyze the original equation and the choices given. $\newline$ Original equation: $-71p = 25$ . $\newline$ Choices involve dividing both sides of the original equation by a number.
Check Choice (A): Step $2$ : Check choice (A) $\frac{-71p}{5} = 5$ . $\newline$ Divide both sides of the original equation by $5$ : $\newline$ $\frac{(–71p)}{5} = \frac{25}{5}$ , $\newline$ $–14.2p = 5$ . $\newline$ This does not match choice (A) since $–14.2p \neq 5$ .
Check Choice (B): Step $3$ : Check choice (B) $\frac{-71p}{-5} = -4$ . $\newline$ Divide both sides of the original equation by $-5$ : $\newline$ $\frac{(-71p)}{-5} = \frac{25}{-5}$ , $\newline$ $14.2p = -5$ . $\newline$ This does not match choice (B) since $14.2p \neq -4$ .
Check Choice (C): Step $4$ : Check choice (C) $\frac{-71p}{-5} = -5$ . Continue from the calculation in Step $3$ : $14.2p = -5$ . This matches choice (C) since $14.2p = -5$ .
Check Choice (D): Step $5$ : Check choice (D) $\frac{-71p}{5} = 3$ . $\newline$ Divide both sides of the original equation by $5$ : $\newline$ $\frac{(\text{–}71p)}{5} = \frac{25}{5}$ , $\newline$ $\text{–}14.2p = 5$ . $\newline$ This does not match choice (D) since $\text{–}14.2p \neq 3$ .