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Scott and William are reading the same book for their English class. Scott is currently on page 150150, and William is on page 6666. Scott reads 1010 pages each day, and William reads 2222 pages each day. Which equation can you use to find dd, the number of days it will take for William to have read as many pages as Scott?\newlineChoices:\newline(A) 150+10d=66+22d150 + 10d = 66 + 22d\newline(B) 150+22d=66+10d150 + 22d = 66 + 10d\newlineHow many days will it take for William to have read as many pages as Scott?\newline___\_\_\_ days

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Q. Scott and William are reading the same book for their English class. Scott is currently on page 150150, and William is on page 6666. Scott reads 1010 pages each day, and William reads 2222 pages each day. Which equation can you use to find dd, the number of days it will take for William to have read as many pages as Scott?\newlineChoices:\newline(A) 150+10d=66+22d150 + 10d = 66 + 22d\newline(B) 150+22d=66+10d150 + 22d = 66 + 10d\newlineHow many days will it take for William to have read as many pages as Scott?\newline___\_\_\_ days
  1. Set Up Equation: Let's set up an equation where the total pages read by Scott equals the total pages read by William after dd days. Scott starts at page 150150 and reads 1010 pages per day, so his total after dd days is 150+10d150 + 10d. William starts at page 6666 and reads 2222 pages per day, so his total after dd days is 66+22d66 + 22d. We want to find the value of dd when these two expressions are equal.
  2. Equation Representation: The correct equation to represent this situation is: \newline150+10d=66+22d150 + 10d = 66 + 22d\newlineThis is because we are looking for the point at which the total pages read by both Scott and William are the same.
  3. Combine Like Terms: To solve for dd, we need to get all the dd terms on one side and the constants on the other. Let's subtract 10d10d from both sides to get:\newline150=66+12d150 = 66 + 12d
  4. Isolate Variable: Now, let's subtract 6666 from both sides to isolate the term with dd: \newline15066=12d150 - 66 = 12d\newline84=12d84 = 12d
  5. Solve for d: Finally, we divide both sides by 1212 to solve for d:\newline8412=d\frac{84}{12} = d\newline7=d7 = d

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