Scott and William are reading the same book for their English class. Scott is currently on page 150, and William is on page 66. Scott reads 10 pages each day, and William reads 22 pages each day. Which equation can you use to find d, the number of days it will take for William to have read as many pages as Scott?Choices:(A) 150+22d=66+10d(B) 150+10d=66+22dHow many days will it take for William to have read as many pages as Scott?____ days
Q. Scott and William are reading the same book for their English class. Scott is currently on page 150, and William is on page 66. Scott reads 10 pages each day, and William reads 22 pages each day. Which equation can you use to find d, the number of days it will take for William to have read as many pages as Scott?Choices:(A) 150+22d=66+10d(B) 150+10d=66+22dHow many days will it take for William to have read as many pages as Scott?____ days
Set Up Equation: Let's set up an equation where the total number of pages read by Scott equals the total number of pages read by William after d days. Scott starts at page 150 and reads 10 pages per day, so after d days, he will have read 150+10d pages. William starts at page 66 and reads 22 pages per day, so after d days, he will have read 66+22d pages. We want to find the value of d when these two expressions are equal.
Write Equation: We can now write the equation as 150+10d=66+22d. This equation represents the point in time when Scott and William will have read the same number of pages.
Solve for d: To solve for d, we need to get all the d terms on one side and the constants on the other. Let's subtract 10d from both sides to get the d terms on one side: 150+10d−10d=66+22d−10d.
Subtract Constants: Simplifying the equation, we get 150=66+12d. Now, let's subtract 66 from both sides to isolate the term with d: 150−66=12d.
Isolate d Term: Performing the subtraction, we find that 84=12d. Now, to solve for d, we divide both sides by 12: 1284=d.
Divide by 12: Calculating the division, we get 7=d. So, it will take William 7 days to have read as many pages as Scott.
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