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Sarah was given this problem:$\newline$The base $b(t)$ of a triangle is decreasing at a rate of $13$ millimeters per minute and the height $h(t)$ of the triangle is increasing at a rate of $6$ millimeters per minute. At a certain instant $t_{0}$, the base is $5$ millimeters and the height is $1$ millimeter. What is the rate of change of the area $A(t)$ of the triangle at that instant (in square millimeters per minute)?$\newline$Which equation should Sarah use to solve the problem?$\newline$Choose $1$ answer:$\newline$(A) $A(t)=\frac{b(t) \cdot h(t)}{2}$$\newline$(B) $A(t)=b(t) \cdot h(t)$$\newline$(C) $A(t)+b(t)+h(t)=180$$\newline$(D) $[A(t)]^{2}=[b(t)]^{2}+[h(t)]^{2}$