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Sam goes to Paw-fect Pets to buy his dog a toy and some food. If he buys a chew toy for $16\$16, he'll have exactly enough money left over to buy 77 cans of dog food. Alternatively, if he buys a ball for $3.50\$3.50, he'll have exactly enough left over to buy 1212 cans of dog food.\newlineWhich equation can you use to find pp, the price of a can of dog food?\newlineChoices:\newline(A) 16+7p=3.5+12p16 + 7p = 3.5 + 12p\newline(B) 167p=3.512p16 - 7p = 3.5 - 12p\newlineWhat is the price of a can of dog food?\newline____ $\_\_\_\_\ \$

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Q. Sam goes to Paw-fect Pets to buy his dog a toy and some food. If he buys a chew toy for $16\$16, he'll have exactly enough money left over to buy 77 cans of dog food. Alternatively, if he buys a ball for $3.50\$3.50, he'll have exactly enough left over to buy 1212 cans of dog food.\newlineWhich equation can you use to find pp, the price of a can of dog food?\newlineChoices:\newline(A) 16+7p=3.5+12p16 + 7p = 3.5 + 12p\newline(B) 167p=3.512p16 - 7p = 3.5 - 12p\newlineWhat is the price of a can of dog food?\newline____ $\_\_\_\_\ \$
  1. Understand the Problem: Understand the problem.\newlineSam has a certain amount of money. When he buys a chew toy for $16\$16, he has enough money left to buy 77 cans of dog food. When he buys a ball for $3.50\$3.50, he has enough money left to buy 1212 cans of dog food. We need to find the price of one can of dog food, which we will call pp.
  2. Set Up Equations: Set up the equations based on the given information.\newlineIf we let the total amount of money Sam has be TT, then we can write two equations based on the information given:\newline11. When he buys the chew toy: T16=7pT - 16 = 7p\newline22. When he buys the ball: T3.50=12pT - 3.50 = 12p
  3. Choose Correct Equation: Choose the correct equation to solve for pp. We need to find an equation that relates the price of the dog food (pp) without involving TT. We can do this by setting the two expressions for the remaining money equal to each other since they both equal TT minus the cost of the toy: T16=7pT - 16 = 7p and T3.50=12pT - 3.50 = 12p So, 7p+16=12p+3.507p + 16 = 12p + 3.50
  4. Solve for p: Solve the equation for p.\newlineNow we need to isolate p. We can do this by subtracting 7p7p from both sides of the equation:\newline7p+167p=12p+3.507p7p + 16 - 7p = 12p + 3.50 - 7p\newlineThis simplifies to:\newline16=5p+3.5016 = 5p + 3.50\newlineNow, subtract 3.503.50 from both sides to isolate the term with p:\newline163.50=5p16 - 3.50 = 5p\newline12.50=5p12.50 = 5p
  5. Divide to Find pp: Divide both sides by 55 to find the value of pp.12.505=5p5\frac{12.50}{5} = \frac{5p}{5}2.50=p2.50 = p

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