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s=11.8(t1.2)2+17s=-11.8(t-1.2)^{2}+17\newlineThe equation models the horizontal distance, ss, in centimeters, of a particular image on a computer screen from the left-hand edge of the screen, tt seconds after appearing. If the image moves in from the left-hand edge of the screen during an on-screen animation, how far to the right does the image travel?\newlineChoose 11 answer:\newline(A) 1.21.2 centimeters\newline(B) 5.25.2 centimeters\newline(C) 1717 centimeters\newline(D) 3434 centimeters

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Q. s=11.8(t1.2)2+17s=-11.8(t-1.2)^{2}+17\newlineThe equation models the horizontal distance, ss, in centimeters, of a particular image on a computer screen from the left-hand edge of the screen, tt seconds after appearing. If the image moves in from the left-hand edge of the screen during an on-screen animation, how far to the right does the image travel?\newlineChoose 11 answer:\newline(A) 1.21.2 centimeters\newline(B) 5.25.2 centimeters\newline(C) 1717 centimeters\newline(D) 3434 centimeters
  1. Plug in t=0t=0: First, let's plug t=0t = 0 into the equation to find the initial position of the image.s=11.8(01.2)2+17s = -11.8(0 - 1.2)^{2} + 17
  2. Calculate initial position: Calculate the initial position:\newlines=11.8(1.2)2+17s = -11.8(-1.2)^2 + 17\newlines=11.8×1.44+17s = -11.8 \times 1.44 + 17\newlines=17.072+17s = -17.072 + 17\newlines=0.072cms = -0.072 \, \text{cm}

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