Rewrite the expression as a product of four linear factors: (x^(2)+2x)^(2)-18(x^(2)+2x)+45 Answer:

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Rewrite the expression as a product of four linear factors:  (x^(2)+2x)^(2)-18(x^(2)+2x)+45 Answer:

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Identify Expression: Let's first identify the expression we need to factor: (x^(2)+2x)^(2)-18(x^(2)+2x)+45 We recognize this as a quadratic in form, where the variable part is (x^2 + 2x). Let's set u = x^2 + 2x to simplify our expression. Our expression becomes: u^2 - 18u + 45 Now we need to factor this quadratic expression.Set Variable: We look for two numbers that multiply to 45 and add up to -18. These numbers are -15 and -3. So we can write our quadratic as: (u - 15)(u - 3)Factor Quadratic: Now we substitute back x^2 + 2x for u to get: (x^2 + 2x - 15)(x^2 + 2x - 3)Find Two Numbers: Next, we need to factor each quadratic. Starting with x^2 + 2x - 15, we look for two numbers that multiply to -15 and add up to 2. These numbers are 5 and -3. So we can write x^2 + 2x - 15 as: (x + 5)(x - 3)Substitute Back: Now we factor x^2 + 2x - 3. We look for two numbers that multiply to -3 and add up to 2. These numbers are 3 and -1. So we can write x^2 + 2x - 3 as: (x + 3)(x - 1)Factor x^2 + 2x - 15: Finally, we combine all the factors to express the original expression as a product of four linear factors: (x + 5)(x - 3)(x + 3)(x - 1)

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}+2 x\right)^{2}-18\left(x^{2}+2 x\right)+45$ $\newline$ Answer:

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Rewrite the expression as a product of four linear factors:\newline(x2+2x)2−18(x2+2x)+45 \left(x^{2}+2 x\right)^{2}-18\left(x^{2}+2 x\right)+45 (x2+2x)2−18(x2+2x)+45\newlineAnswer:

Rewrite the expression as a product of four linear factors: $\newline$ $\left(x^{2}+2 x\right)^{2}-18\left(x^{2}+2 x\right)+45$ $\newline$ Answer: