Put the quadratic into vertex form and state the coordinates of the vertex. y=x^(2)+8x-16 Vertex Form: y= Vertex: (◻,◻)

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Put the quadratic into vertex form and state the coordinates of the vertex.  y=x^(2)+8x-16 Vertex Form:  y= Vertex:  (◻,◻)

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Identify Vertex Form: Identify the vertex form of a parabola. The vertex form of a parabola is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.Complete the Square: Complete the square to transform the given quadratic equation into vertex form. The given quadratic equation is y = x^2 + 8x - 16. To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the x^2 + 8x part. The value needed is (8/2)^2 = 4^2 = 16.Add and Subtract Value: Add and subtract the value found inside the equation. y = x^2 + 8x + 16 - 16 - 16 We added and subtracted 16 to create a perfect square trinomial while keeping the equation balanced.Rewrite with Perfect Square: Rewrite the equation with the perfect square trinomial and the constant term. y = (x^2 + 8x + 16) - 32 Now, the expression in the parentheses is a perfect square trinomial.Factor Perfect Square: Factor the perfect square trinomial. y = (x + 4)^2 - 32 The factored form of x^2 + 8x + 16 is (x + 4)^2.Write in Vertex Form: Write the equation in vertex form and state the coordinates of the vertex. The vertex form of the equation is y = (x + 4)^2 - 32. The vertex (h, k) is found by considering the form y = a(x - h)^2 + k. Here, h = -4 and k = -32. So, the coordinates of the vertex are (-4, -32).

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+8 x-16$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$

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Put the quadratic into vertex form and state the coordinates of the vertex.\newliney=x2+8x−16 y=x^{2}+8 x-16 y=x2+8x−16\newlineVertex Form: y= y= y=\newlineVertex: (□,□) (\square, \square) (□,□)

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+8 x-16$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$