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Put the quadratic into vertex form and state the coordinates of the vertex.

y=x^(2)+2x-24
Vertex Form: 
y=
Vertex: 
(◻,◻)

Put the quadratic into vertex form and state the coordinates of the vertex.\newliney=x2+2x24 y=x^{2}+2 x-24 \newlineVertex Form: y= y= \newlineVertex: (,) (\square, \square)

Full solution

Q. Put the quadratic into vertex form and state the coordinates of the vertex.\newliney=x2+2x24 y=x^{2}+2 x-24 \newlineVertex Form: y= y= \newlineVertex: (,) (\square, \square)
  1. Identify Vertex Form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Complete the Square: Complete the square for the quadratic equation y=x2+2x24y = x^2 + 2x - 24.\newlineTo complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the x2x^2 and 2x2x terms.
  3. Calculate Value: Calculate the value needed to complete the square.\newlineThe coefficient of xx is 22, so we take half of it, which is 11, and then square it to get 12=11^2 = 1.
  4. Add and Subtract: Add and subtract the calculated value inside the equation.\newlineWe add 11 and subtract 11 inside the parentheses to maintain the equality of the equation.\newliney=x2+2x+1124y = x^2 + 2x + 1 - 1 - 24
  5. Rewrite Equation: Rewrite the equation by grouping the perfect square trinomial and the constants.\newliney=(x2+2x+1)25y = (x^2 + 2x + 1) - 25
  6. Factor Trinomial: Factor the perfect square trinomial.\newliney=(x+1)225y = (x + 1)^2 - 25
  7. Write in Vertex Form: Write the equation in vertex form.\newlineThe vertex form of the equation is y=(x+1)225y = (x + 1)^2 - 25.
  8. Identify Vertex Coordinates: Identify the coordinates of the vertex. The vertex form y=a(xh)2+ky = a(x - h)^2 + k gives us the vertex (h,k)(h, k). In our equation y=(x+1)225y = (x + 1)^2 - 25, we have h=1h = -1 and k=25k = -25. Therefore, the vertex is (1,25)(-1, -25).

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