Put the quadratic into vertex form and state the coordinates of the vertex. y=x^(2)+10 x-2 Vertex Form: y= Vertex: (◻,◻)

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Put the quadratic into vertex form and state the coordinates of the vertex.  y=x^(2)+10 x-2 Vertex Form:  y= Vertex:  (◻,◻)

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Identify vertex form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.Convert quadratic equation: Consider the given quadratic equation y = x^2 + 10x - 2. To convert this into vertex form, we need to complete the square.Factor out coefficient: Factor out the coefficient of the x^2 term if it is not 1. In this case, the coefficient of x^2 is 1, so we do not need to factor anything out.Find square of half: Find the square of half the coefficient of the x term to complete the square. Half of the coefficient of x is 10/2, which is 5. Squaring 5 gives us 25.Add and subtract square: Add and subtract the square of half the coefficient of x inside the equation. y = x^2 + 10x + 25 - 25 - 2 This allows us to form a perfect square trinomial while keeping the equation balanced.Rewrite equation grouping: Rewrite the equation grouping the perfect square trinomial and combining the constants. y = (x^2 + 10x + 25) - 27Factor perfect square trinomial: Factor the perfect square trinomial. y = (x + 5)^2 - 27Write in vertex form: Write the equation in vertex form. Vertex Form: y = (x + 5)^2 - 27Identify vertex coordinates: Identify the coordinates of the vertex. The vertex form of the equation is y = a(x - h)^2 + k. Comparing this with our equation y = (x + 5)^2 - 27, we find that h = -5 and k = -27. Therefore, the coordinates of the vertex are (-5, -27).

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+10 x-2$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$

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Put the quadratic into vertex form and state the coordinates of the vertex.\newliney=x2+10x−2 y=x^{2}+10 x-2 y=x2+10x−2\newlineVertex Form: y= y= y=\newlineVertex: (□,□) (\square, \square) (□,□)

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+10 x-2$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$