Q. Put the quadratic into vertex form and state the coordinates of the vertex.y=x2−4x−12Vertex Form: y=Vertex: (□,□)
Identify Vertex Form: Identify the vertex form of a parabola.The vertex form of a parabola is y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Complete the Square:Complete the square to rewrite the quadratic equation in vertex form.Given equation: y=x2−4x−12To complete the square, we need to find a value that, when added and subtracted to the equation, forms a perfect square trinomial with the x2 and −4x terms.The value to complete the square is found by taking half of the coefficient of x and squaring it: (−4/2)2=22=4.
Add and Subtract Value: Add and subtract the value found in Step 2 inside the equation.y=x2−4x+4−4−12y=(x2−4x+4)−16Now, the equation has a perfect square trinomial x2−4x+4 which can be written as (x−2)2.
Rewrite in Vertex Form: Rewrite the equation in vertex form using the perfect square trinomial.y=(x−2)2−16This is the vertex form of the given quadratic equation.
Identify Vertex Coordinates: Identify the coordinates of the vertex from the vertex form.The vertex form of the equation is y=a(x−h)2+k, where (h,k) is the vertex.From the equation y=(x−2)2−16, we can see that h=2 and k=−16.Therefore, the coordinates of the vertex are (2,−16).
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