Put the quadratic into vertex form and state the coordinates of the vertex. y=x^(2)+10 x+9 Vertex Form: y= Vertex: (◻,◻)

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Put the quadratic into vertex form and state the coordinates of the vertex.  y=x^(2)+10 x+9 Vertex Form:  y= Vertex:  (◻,◻)

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Identify vertex form: Identify the vertex form of a parabola. The vertex form of a parabola is given by y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.Given quadratic equation: Consider the given quadratic equation y = x^2 + 10x + 9. To convert this into vertex form, we need to complete the square.Factor out coefficient: Factor out the coefficient of the x^2 term if it is not 1. In this case, the coefficient is already 1, so we can proceed to the next step.Find square of half: Find the square of half the coefficient of the x term to complete the square. Half of the coefficient of x is 10/2 = 5. Squaring this gives us 5^2 = 25.Add and subtract square: Add and subtract the square of half the coefficient of x inside the equation. y = x^2 + 10x + (5^2) - (5^2) + 9 This step ensures that we can form a perfect square trinomial while keeping the equation balanced.Rewrite equation grouping: Rewrite the equation grouping the perfect square trinomial and combining the constants. y = (x^2 + 10x + 25) - 25 + 9 y = (x + 5)^2 - 16Equation in vertex form: Now the equation is in vertex form. Vertex Form: y = (x + 5)^2 - 16Identify vertex coordinates: Identify the coordinates of the vertex from the vertex form. The vertex (h, k) is given by the values inside the parenthesis and the constant term. Here, h = -5 and k = -16. Vertex: (-5, -16)

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+10 x+9$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$

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Put the quadratic into vertex form and state the coordinates of the vertex.\newliney=x2+10x+9 y=x^{2}+10 x+9 y=x2+10x+9\newlineVertex Form: y= y= y=\newlineVertex: (□,□) (\square, \square) (□,□)

Put the quadratic into vertex form and state the coordinates of the vertex. $\newline$ $y=x^{2}+10 x+9$ $\newline$ Vertex Form: $y=$ $\newline$ Vertex: $(\square, \square)$