Q. Polynomial function h is defined as h(x)=2x3−9x2+cx−6, where c is a constant. If 2x−3 is a factor of the polynomial, then what is the value of c ?□
Apply Factor Theorem: Since 2x−3 is a factor of the polynomial h(x), we can use the Factor Theorem which states that if (ax−b) is a factor of a polynomial, then the polynomial will equal zero when x equals ab.
Find x value: Let's find the value of x that makes 2x−3 equal to zero. We solve the equation 2x−3=0 for x.2x=3x=23
Substitute x into h(x): Now we substitute x=23 into the polynomial h(x) and set it equal to zero, because the Factor Theorem tells us that h(23) should be zero if 2x−3 is indeed a factor.h(23)=2(23)3−9(23)2+c(23)−6=0
Calculate h(23): We calculate each term separately:(23)3=827(23)2=49Now we substitute these values into the equation:2(827)−9(49)+c(23)−6=0
Simplify terms: Simplify each term:2(827)=4279(49)=481c(23)=23cNow we have:427−481+23c−6=0
Combine like terms: Combine like terms and simplify the equation:(427−481)+23c−6=0(−454)+23c−6=0−13.5+23c−6=0
Combine constant terms: Combine the constant terms:−13.5−6=−19.5So we have:−19.5+23c=0
Solve for c: Now we solve for c:23c=19.5Multiply both sides by 32 to isolate c:c=(19.5)×(32)c=339c=13
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