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Point 
P is located at -7 . Points 
Q and 
R are each 7 units away from Point 
P. Where are 
Q and 
R located?

Q=◻quadR=

Point P \mathrm{P} is located at 7-7 . Points Q \mathrm{Q} and R \mathrm{R} are each 77 units away from Point P \mathrm{P} . Where are Q \mathrm{Q} and R \mathrm{R} located?\newlineQ=R= \mathrm{Q}=\square \quad \mathrm{R}= \square

Full solution

Q. Point P \mathrm{P} is located at 7-7 . Points Q \mathrm{Q} and R \mathrm{R} are each 77 units away from Point P \mathrm{P} . Where are Q \mathrm{Q} and R \mathrm{R} located?\newlineQ=R= \mathrm{Q}=\square \quad \mathrm{R}= \square
  1. Understand the problem: Understand the problem.\newlineWe need to find the locations of Points QQ and RR, which are each 77 units away from Point PP. Since no direction is specified, we assume that QQ and RR are on a number line with PP at 7-7. There are two possibilities for QQ and RR: either both are to the left of PP, both are to the right of PP, or one is to the left and the other is to the right.
  2. Determine Q location: Determine the location of Point Q.\newlineIf Point Q is 77 units away from Point P and to the right, we add 77 to the position of Point P.\newlineQ=P+7Q = P + 7\newlineQ=7+7Q = -7 + 7\newline$Q = \(0\)
  3. Determine R location: Determine the location of Point R.\(\newline\)If Point R is \(7\) units away from Point P and to the left, we subtract \(7\) from the position of Point P.\(\newline\)\(R = P - 7\)\(\newline\)\(R = -7 - 7\)\(\newline\)\(R = -14\)

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