Point H is located at -1 . Points I and J are each 9 units away from Point H. Where are I and J located? I=◻quadJ=◻

Identify Given Information: Identify the given information and what is being asked. Point H is located at -1 on a number line. Points I and J are each 9 units away from Point H. We need to find the locations of Points I and J.Determine Point I: Determine the location of Point I. Since Point I is 9 units away from Point H, and Point H is at -1, we can find Point I by either adding 9 to -1 or subtracting 9 from -1. Point I could be at -1 + 9 = 8 or at -1 - 9 = -10.Determine Point J: Determine the location of Point J. Point J is also 9 units away from Point H. If we consider the two possible locations for Point I, Point J will be at the opposite side of Point H. Therefore, if Point I is at 8, Point J will be at -10, and vice versa.Check Distances: Check the distance between Points H, I, and J to ensure they are 9 units apart. The distance between Point H at -1 and Point I at 8 is |8 - (-1)| = |8 + 1| = 9 units. The distance between Point H at -1 and Point J at -10 is |-10 - (-1)| = |-10 + 1| = 9 units. Both distances are 9 units, so there is no math error.

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Point
H is located at -1 . Points
I and
J are each 9 units away from Point
H. Where are I and J located?

I=◻quadJ=◻

Point $\mathrm{H}$ is located at $-1$ . Points $\mathrm{I}$ and $\mathrm{J}$ are each $9$ units away from Point $\mathrm{H}$ . Where are I and J located? $\newline$ $\mathrm{I}=\square \quad \mathrm{J}=\square$

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Math Problems

Grade 8

Translations: find the coordinates

Full solution

Q. Point

\mathrm{H}

is located at

-1

. Points

\mathrm{I}

and

\mathrm{J}

are each

9

units away from Point

\mathrm{H}

. Where are I and J located?

\newline

\mathrm{I}=\square \quad \mathrm{J}=\square

Identify Given Information: Identify the given information and what is being asked. $\newline$ Point $H$ is located at $-1$ on a number line. Points $I$ and $J$ are each $9$ units away from Point $H$ . We need to find the locations of Points $I$ and $J$ .
Determine Point I: Determine the location of Point I. $\newline$ Since Point I is $9$ units away from Point H, and Point H is at $-1$ , we can find Point I by either adding $9$ to $-1$ or subtracting $9$ from $-1$ . Point I could be at $-1 + 9 = 8$ or at $-1 - 9 = -10$ .
Determine Point J: Determine the location of Point J. $\newline$ Point J is also $9$ units away from Point H. If we consider the two possible locations for Point I, Point J will be at the opposite side of Point H. Therefore, if Point I is at $8$ , Point J will be at $-10$ , and vice versa.
Check Distances: Check the distance between Points H, I, and J to ensure they are $9$ units apart. $\newline$ The distance between Point H at $-1$ and Point I at $8$ is $|8 - (-1)| = |8 + 1| = 9$ units. $\newline$ The distance between Point H at $-1$ and Point J at $-10$ is $|-10 - (-1)| = |-10 + 1| = 9$ units. $\newline$ Both distances are $9$ units, so there is no math error.