Point J is located at -13 . Points K and L are each 6 units away from Point J. Where are K and L located? K=◻quadL=◻

Identify Initial Position: Identify the initial position of Point J. Point J is located at -13 on a number line.Determine Positions of Points: Determine the positions of Points K and L relative to Point J. Since Points K and L are each 6 units away from Point J, we need to find two points: one that is 6 units to the left of Point J and one that is 6 units to the right of Point J.Calculate Position of K: Calculate the position of Point K. To find Point K, which is 6 units to the left of Point J, we subtract 6 from the position of Point J. K = -13 - 6 = -19Calculate Position of L: Calculate the position of Point L. To find Point L, which is 6 units to the right of Point J, we add 6 to the position of Point J. L = -13 + 6 = -7

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Point
J is located at -13 . Points
K and
L are each 6 units away from Point
J. Where are
K and
L located?

K=◻quadL=◻

Point $\mathrm{J}$ is located at $-13$ . Points $\mathrm{K}$ and $\mathrm{L}$ are each $6$ units away from Point $\mathrm{J}$ . Where are $\mathrm{K}$ and $\mathrm{L}$ located? $\newline$ $\mathrm{K}=\square \quad \mathrm{L}=\square$

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Math Problems

Grade 8

Translations: find the coordinates

Full solution

Q. Point

\mathrm{J}

is located at

-13

. Points

\mathrm{K}

and

\mathrm{L}

are each

6

units away from Point

\mathrm{J}

. Where are

\mathrm{K}

and

\mathrm{L}

located?

\newline

\mathrm{K}=\square \quad \mathrm{L}=\square

Identify Initial Position: Identify the initial position of Point J. Point J is located at $-13$ on a number line.
Determine Positions of Points: Determine the positions of Points $K$ and $L$ relative to Point $J$ . Since Points $K$ and $L$ are each $6$ units away from Point $J$ , we need to find two points: one that is $6$ units to the left of Point $J$ and one that is $6$ units to the right of Point $J$ .
Calculate Position of K: Calculate the position of Point K. $\newline$ To find Point K, which is $6$ units to the left of Point J, we subtract $6$ from the position of Point J. $\newline$ $K = -13 - 6 = -19$
Calculate Position of L: Calculate the position of Point L. $\newline$ To find Point L, which is $6$ units to the right of Point J, we add $6$ to the position of Point J. $\newline$ $L = -13 + 6 = -7$