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P(t)=30(2)(t18)P(t)=30(2)^{\left(\frac{t}{18}\right)}\newlineThe function models PP, the amount of bacteria, in colony-forming units, in a bacteria culture after tt minutes of growth. How many colony-forming units of bacteria are in the bacteria culture after 9090 minutes?\newlineChoose 11 answer:\newline(A) 3×1023\times10^{2}\newline(B) 9.6×1029.6 \times10^{2}\newline(C) 5.4×1035.4 \times10^{3}\newline(D) 2.43×1072.43 \times10^{7}

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Q. P(t)=30(2)(t18)P(t)=30(2)^{\left(\frac{t}{18}\right)}\newlineThe function models PP, the amount of bacteria, in colony-forming units, in a bacteria culture after tt minutes of growth. How many colony-forming units of bacteria are in the bacteria culture after 9090 minutes?\newlineChoose 11 answer:\newline(A) 3×1023\times10^{2}\newline(B) 9.6×1029.6 \times10^{2}\newline(C) 5.4×1035.4 \times10^{3}\newline(D) 2.43×1072.43 \times10^{7}
  1. Identify function and value of t: Identify the given function and the value of tt for which we need to find P(t)P(t). The function given is P(t)=30(2)t18P(t) = 30(2)^{\frac{t}{18}}, and we need to find the amount of bacteria after t=90t = 90 minutes.
  2. Substitute value of t into function: Substitute the value of tt into the function to calculate P(90)P(90). \newlineP(90)=30(2)(90)/(18)P(90) = 30(2)^{(90)/(18)}
  3. Simplify the exponent: Simplify the exponent by dividing 9090 by 1818.9018=5\frac{90}{18} = 5
  4. Substitute simplified exponent: Substitute the simplified exponent back into the function.\newlineP(90)=30(2)5P(90) = 30(2)^5
  5. Calculate exponent: Calculate 22 raised to the power of 55.\newline25=322^5 = 32
  6. Multiply by 3030: Multiply the result by 3030 to find P(90)P(90). \newlineP(90)=30×32P(90) = 30 \times 32
  7. Perform multiplication: Perform the multiplication to find the number of colony-forming units. P(90)=960P(90) = 960
  8. Write final answer in scientific notation: Write the final answer in scientific notation if necessary.\newline960960 can be written as 9.6×1029.6 \times 10^2.

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