Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

p(m)=100((1)/(2))^((m)/( 27))
Bismuth-199 is a radioactive isotope that decays over time. The half-life of a radioactive isotope is the amount of time it takes for 
(1)/(2) of the isotopes in a sample to decay. The function models the percent of bismuth-199 remaining in a sample after 
m minutes. What is the meaning of the number 27 in the function?
Choose 1 answer:
(A) The amount of bismuth- 199 in the sample decreases by 
27% every 
(1)/(2) minute.
(B) The sample is initially composed of 
27% bismuth- 199 .
(C) The half-life of bismuth-199 is 13.5 minutes.
(D) The half-life of bismuth-199 is 27 minutes.

p(m)=100(12)m27 p(m)=100\left(\frac{1}{2}\right)^{\frac{m}{27}} \newlineBismuth199-199 is a radioactive isotope that decays over time. The half-life of a radioactive isotope is the amount of time it takes for 12 \frac{1}{2} of the isotopes in a sample to decay. The function models the percent of bismuth199-199 remaining in a sample after m m minutes. What is the meaning of the number 2727 in the function?\newlineChoose 11 answer:\newline(A) The amount of bismuth- 199199 in the sample decreases by 27% 27 \% every 12 \frac{1}{2} minute.\newline(B) The sample is initially composed of 27% 27 \% bismuth- 199199 .\newline(C) The half-life of bismuth199-199 is 1313.55 minutes.\newline(D) The half-life of bismuth199-199 is 2727 minutes.

Full solution

Q. p(m)=100(12)m27 p(m)=100\left(\frac{1}{2}\right)^{\frac{m}{27}} \newlineBismuth199-199 is a radioactive isotope that decays over time. The half-life of a radioactive isotope is the amount of time it takes for 12 \frac{1}{2} of the isotopes in a sample to decay. The function models the percent of bismuth199-199 remaining in a sample after m m minutes. What is the meaning of the number 2727 in the function?\newlineChoose 11 answer:\newline(A) The amount of bismuth- 199199 in the sample decreases by 27% 27 \% every 12 \frac{1}{2} minute.\newline(B) The sample is initially composed of 27% 27 \% bismuth- 199199 .\newline(C) The half-life of bismuth199-199 is 1313.55 minutes.\newline(D) The half-life of bismuth199-199 is 2727 minutes.
  1. Understand function p(m)p(m): Understand the function p(m)=100(12)m27p(m)=100\left(\frac{1}{2}\right)^{\frac{m}{27}} and identify what each part represents.\newlineThe function p(m)p(m) represents the percent of bismuth199-199 remaining after mm minutes. The base (12)\left(\frac{1}{2}\right) indicates that we are dealing with a half-life decay process. The exponent (m27)\left(\frac{m}{27}\right) suggests that the time mm is being scaled by a factor related to the half-life.
  2. Analyze options given: Analyze the options given to determine which one correctly describes the number 2727 in the function.\newlineOption (A) suggests that the amount of bismuth-199199 decreases by 27%27\% every half minute, which is not indicated by the function. The function shows a half-life decay, not a percentage decrease per time unit.
  3. Continue analyzing options: Continue analyzing the options.\newlineOption (B) suggests that the sample is initially composed of 27%27\% bismuth-199199, which is not related to the number 2727 in the exponent and does not make sense in the context of the function.
  4. Analyze option (D): Continue analyzing the options.\newlineOption (C) suggests that the half-life of bismuth-\newline199199 is 13.513.5 minutes. This would mean that the exponent should be (m/13.5)(m/13.5) to represent the half-life in the function, which is not the case.
  5. Analyze option (D): Continue analyzing the options.\newlineOption (C) suggests that the half-life of bismuth199-199 is 13.513.5 minutes. This would mean that the exponent should be (m/13.5)(m/13.5) to represent the half-life in the function, which is not the case.Analyze option (D).\newlineOption (D) suggests that the half-life of bismuth199-199 is 2727 minutes. This aligns with the function because the exponent (m/27)(m/27) means that every time mm equals 2727, the quantity of bismuth199-199 is halved. Therefore, the number 2727 represents the half-life of bismuth199-199 in minutes.

More problems from Evaluate two-variable equations: word problems