Nora uploaded a funny video on her website, which rapidly gains views over time. The following function gives the number of views t days after Nora uploaded the video:V(t)=100⋅e0.4tWhat is the instantaneous rate of change of the number of views 4 days after the video was uploaded?Choose 1 answer:(A) 198 views(B) 198 views per day(C) 495 views(D) 495 views per day
Q. Nora uploaded a funny video on her website, which rapidly gains views over time. The following function gives the number of views t days after Nora uploaded the video:V(t)=100⋅e0.4tWhat is the instantaneous rate of change of the number of views 4 days after the video was uploaded?Choose 1 answer:(A) 198 views(B) 198 views per day(C) 495 views(D) 495 views per day
Take Derivative of V(t): To find the instantaneous rate of change, we need to take the derivative of V(t) with respect to t. V(t)=100⋅e0.4t dtdV=100⋅0.4⋅e0.4t
Evaluate at t=4: Now we need to evaluate the derivative at t=4 days.dtdV=100×0.4×e(0.4×4)
Simplify the Expression: Simplify the expression. dtdV=40⋅e1.6
Calculate e1.6: Use a calculator to find the value of e1.6.e1.6≈4.953 (rounded to three decimal places)
Multiply by 40: Multiply 40 by the value of e1.6. dtdV=40×4.953
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