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Mandisa's teacher gave her a flow chart (below) and asked her to find 
lim_(x rarr-1)f(x) for 
f(x)=(1+sqrt(5x+30))/(x^(2)-1).
Calculating 
lim_(x rarr a)f(x)

Mandisa's teacher gave her a flow chart (below) and asked her to find limx1f(x) \lim _{x \rightarrow-1} f(x) for f(x)=1+5x+30x21 f(x)=\frac{1+\sqrt{5 x+30}}{x^{2}-1} .\newlineCalculating limxaf(x) \lim _{x \rightarrow a} f(x)

Full solution

Q. Mandisa's teacher gave her a flow chart (below) and asked her to find limx1f(x) \lim _{x \rightarrow-1} f(x) for f(x)=1+5x+30x21 f(x)=\frac{1+\sqrt{5 x+30}}{x^{2}-1} .\newlineCalculating limxaf(x) \lim _{x \rightarrow a} f(x)
  1. Check for Undefined: First, substitute x=1 x = -1 into the function to check if it's defined. \newlinef(1)=1+5(1)+30(1)21=1+2511=1+50=60 f(-1) = \frac{1 + \sqrt{5(-1) + 30}}{(-1)^2 - 1} = \frac{1 + \sqrt{25}}{1 - 1} = \frac{1 + 5}{0} = \frac{6}{0} \newlineSince the denominator is 00, the function is undefined at x=1 x = -1 .
  2. Factor Denominator: Next, factor the denominator to see if we can simplify the function.\newlinex21=(x1)(x+1) x^2 - 1 = (x - 1)(x + 1) \newlineSo, \newlinef(x)=1+5x+30(x1)(x+1) f(x) = \frac{1 + \sqrt{5x + 30}}{(x - 1)(x + 1)}
  3. Apply L'Hôpital's Rule: Now, let's use the limit properties and L'Hôpital's Rule since we have a 00\frac{0}{0} form.\newlinelimx11+5x+30(x1)(x+1) \lim_{x \to -1} \frac{1 + \sqrt{5x + 30}}{(x - 1)(x + 1)} \newlineDifferentiate the numerator and the denominator separately.\newlineNumerator: \newlineddx(1+5x+30)=ddx(1)+ddx(5x+30)=0+525x+30=525x+30 \frac{d}{dx} (1 + \sqrt{5x + 30}) = \frac{d}{dx} (1) + \frac{d}{dx} (\sqrt{5x + 30}) = 0 + \frac{5}{2\sqrt{5x + 30}} = \frac{5}{2\sqrt{5x + 30}} \newlineDenominator:\newlineddx((x1)(x+1))=ddx(x21)=2x \frac{d}{dx} ((x - 1)(x + 1)) = \frac{d}{dx} (x^2 - 1) = 2x \newlineSo, \newlinelimx1525x+302x=limx154x5x+30 \lim_{x \to -1} \frac{\frac{5}{2\sqrt{5x + 30}}}{2x} = \lim_{x \to -1} \frac{5}{4x\sqrt{5x + 30}}
  4. Simplify Limit: Substitute x=1 x = -1 into the simplified limit.\newlinelimx154x5x+30=54(1)5(1)+30=5425=545=520=14 \lim_{x \to -1} \frac{5}{4x\sqrt{5x + 30}} = \frac{5}{4(-1)\sqrt{5(-1) + 30}} = \frac{5}{-4\sqrt{25}} = \frac{5}{-4 \cdot 5} = \frac{5}{-20} = -\frac{1}{4}

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