Mackenzie and Ernest weighed their pet cats. Mackenzie's cat weighed $13\frac{3}{8}$ pounds and Ernest's cat weighed $5\frac{7}{8}$ pounds. How much more did Mackenzie's cat weigh than Ernest's cat? $\newline$ Write your answer as a fraction or as a whole or mixed number. $\newline$ $\_\_\_\_$ pounds

Full solution

Q. Mackenzie and Ernest weighed their pet cats. Mackenzie's cat weighed

13\frac{3}{8}

pounds and Ernest's cat weighed

5\frac{7}{8}

pounds. How much more did Mackenzie's cat weigh than Ernest's cat?

\newline

Write your answer as a fraction or as a whole or mixed number.

\newline

\_\_\_\_

pounds

Convert to Improper Fractions: Convert the weights of the cats from mixed numbers to improper fractions for easier calculation. Mackenzie's cat: $13 \frac{3}{8} = \frac{107}{8}$ . Ernest's cat: $5 \frac{7}{8} = \frac{47}{8}$ .
Subtract Weights: Subtract Ernest's cat's weight from Mackenzie's cat's weight to find the difference. $\frac{107}{8} - \frac{47}{8} = \frac{60}{8}$ .
Simplify Result: Simplify the result to find the weight difference in simplest form. $\frac{60}{8} = 7 \frac{1}{2}$ pounds.