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log_(9)729=

log9729= \log _{9} 729=

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Q. log9729= \log _{9} 729=
  1. Identify Relationship: Identify the relationship between the base of the logarithm and the number.\newlineThe base of the logarithm is 99, and we need to find the exponent that 99 must be raised to in order to get 729729.
  2. Express as Power: Express 729729 as a power of 99. We know that 99 is 33 squared (9=329 = 3^2), and 729729 is 33 to the sixth power (729=36729 = 3^6). Therefore, 729729 can be expressed as (32)3(3^2)^3.
  3. Rewrite Logarithm: Rewrite the logarithm using the new expression for 729729.\newlinelog9(729)\log_{9}(729) becomes log9((32)3)\log_{9}((3^2)^3).
  4. Apply Power Property: Apply the power property of logarithms.\newlineThe power property states that logb(PQ)=Qlogb(P)\log_b(P^Q) = Q \cdot \log_b(P). Therefore, log9((32)3)\log_{9}((3^2)^3) becomes 3log9(32)3 \cdot \log_{9}(3^2).
  5. Simplify Logarithm: Simplify the logarithm inside the expression.\newlineSince 99 is 33 squared, log9(32)\log_{9}(3^2) is asking "to what power do we raise 99 to get 33 squared?" The answer is 11 because 99 to the power of 11 is 99, and 33 squared is also 99. So, 3311.
  6. Multiply by Exponent: Multiply the simplified logarithm by the exponent.\newlineNow we have 3×log9(32)3 \times \log_{9}(3^2) which simplifies to 3×13 \times 1.
  7. Calculate Final Value: Calculate the final value.\newlineMultiplying 33 by 11 gives us the final answer of 33.

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