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log_(81)(1)/(3)=

log8113= \log _{81} \frac{1}{3}=

Full solution

Q. log8113= \log _{81} \frac{1}{3}=
  1. Evaluate logarithm with base 8181: We need to evaluate the logarithm of 13\frac{1}{3} with base 8181. The base of the logarithm is 8181, which is 343^4.
  2. Express 13\frac{1}{3} as 313^{-1}: We can express 13\frac{1}{3} as 313^{-1} since dividing by 33 is the same as multiplying by 33 to the power of 1-1.
  3. Rewrite logarithm with new expressions: Now we rewrite the logarithm using the new expressions for the base and the argument: log34(31)\log_{3^4}(3^{-1}).
  4. Apply change of base formula: We can apply the change of base formula for logarithms, which states that logb(a)=logc(a)logc(b)\log_b(a) = \frac{\log_c(a)}{\log_c(b)}. In this case, we can change the base to 33 because it is a common base for both 8181 and 13\frac{1}{3}. This gives us log3(31)log3(34)\frac{\log_3(3^{-1})}{\log_3(3^4)}.
  5. Simplify logarithmic expressions: Since the logarithm of a number to the same base is 11, log3(31)\log_3(3^{-1}) simplifies to 1-1 and log3(34)\log_3(3^4) simplifies to 44.
  6. Divide the results: Now we divide the two results: 1/4-1 / 4.
  7. Final answer: The final answer is 14-\frac{1}{4}. This completes the evaluation of the logarithm.

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