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log_(3)243=

log3243= \log _{3} 243=

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Q. log3243= \log _{3} 243=
  1. Identify base, argument, and unknown exponent: Identify the base (), the argument (), and the unknown exponent () in the logarithmic equation _{(33)}243243 = . In this case,  = 33 and  = 243243. We need to find the value of  such that 33^ = 243243.
  2. Recall logarithms and exponents relationship: Recall the relationship between logarithms and exponents: logbx=y\log_{b}x = y is equivalent to by=xb^{y} = x.\newlineWe can rewrite the logarithmic equation in exponential form: 3y=2433^{y} = 243.
  3. Determine the value of yy: Determine the value of yy by finding the exponent that makes 3y3^y equal to 243243.\newlineWe know that 35=2433^5 = 243 because 3×3×3×3×3=2433 \times 3 \times 3 \times 3 \times 3 = 243.\newlineTherefore, y=5y = 5.
  4. Write the final exponential equation: Write the final exponential equation using the value of yy found in the previous step.\newlineThe exponential form of the equation is 35=2433^5 = 243.

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