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Liz is comparing two options to go zip-lining with some friends. The zip line at Blackberry Lake costs $30\$30 per person, plus a $40\$40 charge to rent equipment for the group. The zip line at Mount Oak costs $45\$45 per person, with no additional charge for equipment. Liz also has a coupon for $20\$20 off the total price at Mount Oak.\newlineWhich equation can you use to find pp, the number of people who would need to go zip-lining for the two options to cost the same?\newlineChoices:\newline(A) 30p+40=45p+2030p + 40 = 45p + 20\newline(B) 30p+40=45p2030p + 40 = 45p - 20\newlineHow many people would need to go zip-lining for the two options to cost the same?\newline___\_\_\_ people\newline

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Q. Liz is comparing two options to go zip-lining with some friends. The zip line at Blackberry Lake costs $30\$30 per person, plus a $40\$40 charge to rent equipment for the group. The zip line at Mount Oak costs $45\$45 per person, with no additional charge for equipment. Liz also has a coupon for $20\$20 off the total price at Mount Oak.\newlineWhich equation can you use to find pp, the number of people who would need to go zip-lining for the two options to cost the same?\newlineChoices:\newline(A) 30p+40=45p+2030p + 40 = 45p + 20\newline(B) 30p+40=45p2030p + 40 = 45p - 20\newlineHow many people would need to go zip-lining for the two options to cost the same?\newline___\_\_\_ people\newline
  1. Setup Equation: Let's set up the equation for the total cost of zip-lining for pp people at Blackberry Lake and Mount Oak, respectively. At Blackberry Lake, the cost is $30\$30 per person plus a $40\$40 equipment fee. At Mount Oak, the cost is $45\$45 per person minus the $20\$20 coupon.\newlineThe equation to represent this scenario is:\newlineTotal cost at Blackberry Lake = Total cost at Mount Oak\newline30p+40=45p2030p + 40 = 45p - 20 (after applying the coupon at Mount Oak)
  2. Solve for pp: Now we need to solve for pp. To do this, we will first move all terms involving pp to one side of the equation and the constant terms to the other side. We can subtract 30p30p from both sides to get:\newline30p+4030p=45p2030p30p + 40 - 30p = 45p - 20 - 30p\newlineThis simplifies to:\newline40=15p2040 = 15p - 20
  3. Isolate Variable pp: Next, we will isolate the variable pp by moving the constant terms to the other side. We add 2020 to both sides of the equation:\newline40+20=15p20+2040 + 20 = 15p - 20 + 20\newlineThis simplifies to:\newline60=15p60 = 15p
  4. Divide to Solve: Finally, we divide both sides by 1515 to solve for pp: \newline6015=15p15\frac{60}{15} = \frac{15p}{15}\newlineThis simplifies to:\newline4=p4 = p

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