Liz is comparing two options to go zip-lining with some friends. The zip line at Blackberry Lake costs $30 per person, plus a $40 charge to rent equipment for the group. The zip line at Mount Oak costs $45 per person, with no additional charge for equipment. Liz also has a coupon for $20 off the total price at Mount Oak.Which equation can you use to find p, the number of people who would need to go zip-lining for the two options to cost the same?Choices:(A) 30p+40=45p−20(B) 30p+40=45p+20How many people would need to go zip-lining for the two options to cost the same?___ people
Q. Liz is comparing two options to go zip-lining with some friends. The zip line at Blackberry Lake costs $30 per person, plus a $40 charge to rent equipment for the group. The zip line at Mount Oak costs $45 per person, with no additional charge for equipment. Liz also has a coupon for $20 off the total price at Mount Oak.Which equation can you use to find p, the number of people who would need to go zip-lining for the two options to cost the same?Choices:(A) 30p+40=45p−20(B) 30p+40=45p+20How many people would need to go zip-lining for the two options to cost the same?___ people
Set Up Equation: First, let's set up the equation to compare the costs of both zip-lining options. Blackberry Lake costs $30 per person plus a $40 group equipment fee, so the total cost for p people is 30p+40. Mount Oak costs $45 per person, but Liz has a $20 coupon, so the total cost for p people is 45p−20. The equation to find when both costs are the same is 30p+40=45p−20.
Solve Equation: Step 1: Now, solve the equation 30p+40=45p−20. First, subtract 30p from both sides to get all terms involving p on one side: 40=15p−20.
Solve Equation: Step 2: Next, add 20 to both sides to isolate the term with p: 60=15p.
Solve Equation: Step 3: Finally, divide both sides by 15 to solve for p: p=1560.
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