Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

lim_(x rarr0)tan(x)=?
Choose 1 answer:
(A) -1
(B) 0
(C) 1
(D) The limit doesn't exist.

limx0tan(x)=? \lim _{x \rightarrow 0} \tan (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.

Full solution

Q. limx0tan(x)=? \lim _{x \rightarrow 0} \tan (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.
  1. Understanding the tangent function: To solve the limit of tan(x)\tan(x) as xx approaches 00, we need to understand the behavior of the tangent function near 00. The tangent function is defined as the ratio of the sine function to the cosine function, so we can express tan(x)\tan(x) as sin(x)/cos(x)\sin(x)/\cos(x).
  2. Applying limit properties: We know that the limit of sin(x)\sin(x) as xx approaches 00 is 00, and the limit of cos(x)\cos(x) as xx approaches 00 is 11. This is a direct application of the limit properties of trigonometric functions.
  3. Dividing the limits: Using the limit properties, we can divide the limits of the numerator and the denominator as long as the limit of the denominator is not 00. Since cos(0)=1\cos(0) = 1, we can safely divide the limits.
  4. Calculating the limit of tan(x)\tan(x): Now we calculate the limit of tan(x)\tan(x) as xx approaches 00 by dividing the limits of sin(x)\sin(x) and cos(x)\cos(x):limx0tan(x)=limx0(sin(x)cos(x))=limx0sin(x)limx0cos(x)=01=0\lim_{x \to 0} \tan(x) = \lim_{x \to 0} \left(\frac{\sin(x)}{\cos(x)}\right) = \frac{\lim_{x \to 0} \sin(x)}{\lim_{x \to 0} \cos(x)} = \frac{0}{1} = 0.
  5. Conclusion: Therefore, the limit of tan(x)\tan(x) as xx approaches 00 is 00, which corresponds to option (B).

More problems from Find derivatives of logarithmic functions