Identify Limit Form: Identify the form of the limit to determine the method of solution.As x approaches 0, both cos(3x) and cos(2x) approach 1. Therefore, ln(cos(3x)) and ln(cos(2x)) both approach ln(1), which is 0. This gives us a 0/0 indeterminate form, which suggests that we can use L'Hôpital's Rule to evaluate the limit.
Apply L'Hôpital's Rule: Apply L'Hôpital's Rule. L'Hôpital's Rule states that if the limit of f(x)/g(x) as x approaches a value c is in the indeterminate form 0/0 or ∞/∞, then the limit is the same as the limit of f′(x)/g′(x) as x approaches c, provided that the derivatives exist and the limit of f′(x)/g′(x) is determinate.
Differentiate Numerator and Denominator: Differentiate the numerator and denominator separately.The derivative of ln(cos(3x)) with respect to x is cos(3x)1⋅(−sin(3x))⋅3, using the chain rule.The derivative of ln(cos(2x)) with respect to x is cos(2x)1⋅(−sin(2x))⋅2, also using the chain rule.
Simplify Derivatives: Simplify the derivatives.The derivative of ln(cos(3x)) simplifies to −3tan(3x).The derivative of ln(cos(2x)) simplifies to −2tan(2x).
Apply L'Hôpital's Rule: Apply L'Hôpital's Rule by taking the limit of the derivatives.limx→0(−2tan(2x)−3tan(3x))=limx→0(2tan(2x)3tan(3x))
Evaluate Simplified Expression: Evaluate the limit of the simplified expression.As x approaches 0, tan(3x) approaches 3x and tan(2x) approaches 2x because tan(x) is approximately equal to x for small values of x.Therefore, the limit becomes limx→0(3×3x/2×2x)=limx→0(9x/4x).
Simplify and Evaluate Limit: Simplify the expression and evaluate the limit.The x's cancel out, and we are left with 49. Since there are no x terms left, the limit is simply 49.
More problems from Find derivatives of logarithmic functions