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lim_(x rarr0)csc(x)=?
Choose 1 answer:
(A) -1
(B) 0
(C) 1
(D) The limit doesn't exist.

limx0csc(x)=? \lim _{x \rightarrow 0} \csc (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.

Full solution

Q. limx0csc(x)=? \lim _{x \rightarrow 0} \csc (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 00\newline(C) 11\newline(D) The limit doesn't exist.
  1. Definition of csc(x)csc(x): To solve the limit of csc(x)csc(x) as xx approaches 00, we need to understand the definition of csc(x)csc(x), which is 1sin(x)\frac{1}{\sin(x)}. We are looking for the limit of 1sin(x)\frac{1}{\sin(x)} as xx approaches 00.
  2. Behavior of sin(x) as x approaches 00: We know that sin(0)=0\sin(0) = 0. As xx approaches 00, sin(x)\sin(x) approaches 00 as well. Therefore, we are essentially looking at the behavior of 10\frac{1}{0} as xx approaches 00.
  3. Undefined expression 10\frac{1}{0}: The expression 10\frac{1}{0} is undefined, which means that as sin(x)\sin(x) gets closer and closer to 00, 1sin(x)\frac{1}{\sin(x)} (or csc(x)\csc(x)) grows without bound. This suggests that the limit does not exist because the function does not approach a finite value.
  4. Limit of csc(x)\csc(x) as xx approaches 00: Since the limit of csc(x)\csc(x) as xx approaches 00 does not approach a finite value and instead grows without bound, the correct answer is (D) The limit doesn't exist.

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