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lim_(x rarr-1)(6x^(2)+5x-1)=

limx1(6x2+5x1)= \lim _{x \rightarrow-1}\left(6 x^{2}+5 x-1\right)=

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Q. limx1(6x2+5x1)= \lim _{x \rightarrow-1}\left(6 x^{2}+5 x-1\right)=
  1. Identify function and point: Identify the function and the point at which we need to find the limit. We are given the function f(x)=6x2+5x1f(x) = 6x^2 + 5x - 1 and we need to find the limit as xx approaches 1-1.
  2. Substitute value into function: Substitute the value of xx into the function.\newlineSince the function is a polynomial, which is continuous everywhere, we can directly substitute the value of x=1x = -1 into the function to find the limit.\newlinef(1)=6(1)2+5(1)1f(-1) = 6(-1)^2 + 5(-1) - 1
  3. Calculate function value: Calculate the value of the function at x=1x = -1.f(1)=6(1)+5(1)1f(-1) = 6(1) + 5(-1) - 1f(1)=651f(-1) = 6 - 5 - 1f(1)=0f(-1) = 0

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